Question

A minor league baseball team plays 80 games in a season. if the team won 14 more than twicetwice as many games as they​ lost, how many wins and losses did the team​ have?

Answer 1

We can put this as an equation as N being the number of games?. So the equations will be equal to 2n+14 (the numbers of wins) and 2n (the number of losses) this would give you (2n+14)+2n which is 4n+14=80, you have to subtract 14 to both sides to leave N alone, and that would give you 4n=66, now we have to divide, "Why do you need to divide?" To leave N alone, you always have to do the opposite to both sides. So once we divide both sides by 4, we get n=16.5 Now we replace n=16.5
So the number of wins was 2n+14 which would give you 2(16.5)+14, which is 47 games won
And the number of losses is 2n which is 2(16.5) and that would be equal to 33
So the team won 47 games and lost 33 games
47+33=80
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