The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the 
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that 
, 
, 
and 
, then the resulting vector is:
![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (), in degrees, by the following <em>trigonometric</em> expression:
(3)
The bearing of the plane is approximately 178.037°.
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
Hey buddy I am here to help!
total outcomes r = 36
multiples of 3 = 3,6
total outcomes of multiple fo 3 = 12
12/36 = 1/3
1/3 is the answer
Hope it helps!
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Answer:
They were going at 15 mph. Scroll down for step-by-step! :)
Step-by-step explanation:
2 hours, 30 miles. 30 divided by 2 :)
Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
