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Harlamova29_29 [7]
3 years ago
8

-4x +39 > -29 what is the answer for this question

Mathematics
1 answer:
ratelena [41]3 years ago
8 0

Answer:

<h2>x < 17</h2>

Step-by-step explanation:

-4x +39 > -29

⇔

-4x > -29 - 39

⇔

-4x > -68

⇔

-x > -68/4

⇔

-x > -17

⇔

x < 17

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Consider the geometric sequence 16, 8, a, 2, b, ... (a) Write down the common
Artist 52 [7]

Find the common ratio by dividing.

16 / 8 = 2

8 / a = 2

2 / b = 2

The common ratio is 2.

Since we need to find the values of a and b, use the common ratio to solve for them.

8 / 2 = 4 (a)

2 / 2 = 1 (b)

Now, we know that first 5 terms.

We can solve for the 8th term using the previous terms and the common ratio.

6th term: 1 / 2 = 0.5

7th term: 0.5 / 2 = 0.25

8th term: 0.25 / 2 = 0.125

Part A: 2

Part B: a = 4, b = 1

Part C: 0.125

Best of Luck!

3 0
3 years ago
BRAINIEST ANSWER PLEASE HELP OFFERING 30 POINTS!!!!
Anastasy [175]

Answer:

The answer is 14 quarters and six dimes

Step-by-step explanation:

-.1(D+Q=20)

.10D+.25Q=4.10    -.1D-.1Q=-2

                             .1D+.25Q=4.10

------------------------------------------------------

                            .15Q=2.10/.15(both sides)

Q=14 which leaves you needing 60 more cents so 6 dimes

3 0
3 years ago
Read 2 more answers
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
45 Points!!!
yawa3891 [41]

Answer:

5.3

Step-by-step explanation:

subract

4 0
4 years ago
1/9,1/3,5/9 find the rule
anastassius [24]
It’s going up by 2/9 . if you did it for the first one it’d b 3/9 which is 1/3
3 0
4 years ago
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