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Nataliya [291]
3 years ago
8

The allele for a widows peak has complete dominance over the allele for a straight hairline (w)what is the probability of a man

with a straight hairline (ww) and a woman with a widows peak WW having an offspring without a widows peak
Biology
2 answers:
dalvyx [7]3 years ago
8 0
I would think it's 25%.
nataly862011 [7]3 years ago
3 0
If you use a Punnett square, you see that there is a 25% chance of a homozygous dominant offspring, a 50% chance of a heterozygous dominant offspring, and a 25% chance of a homozygous recessive offspring. The homozygous recessive individual is the only one that will exhibit the non widows peak phenotype, therefore the chance of this is 25%
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Julli [10]
Consider this:

Each parent has two sex chromosomes.
The mother, as a female, has chromosomes XX.
The father, a male, has XY.

The mother will pass on one sex chromosome to the baby, as will the father.
The mother can only pass on an X.
The father, however, has a 50/50 chance of passing on an X or Y.
XX would make a female and XY would make a male.

Simply put, the sex chromosome from your mother is fixed, it's going to be an X no matter what. It's which sex chromosome your father passes on that determines your sex.

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omeli [17]

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B) hypertension and bradycardia.

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