Answer:
The correct option is Plane A because it was 27.43 miles away ....
Step-by-step explanation:
Angle of elevation of plane A=41 °
Angle of elevation of plane B=43°
height of planes=18 miles
let Δabc be the right triangle formed by the plane A and Δabd be the right triangle formed by the plane B
then ab=18miles
∠c, angle of elevation of plane A=41 °
then distance bc=?
sinc=ab/bc
sin(41°)=18/bc
bc=18/0.65
bc=27.437 miles
Now
∠d, angle of elevation of plane B=43°
then distance bd=?
sinc=ab/bd
sin(43°)=18/bd
bd=18/0.68199
bd=26.393 miles
As bc>bd
The correct option is Plane A because it was 27.43 miles away ....
