A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in
2 answers:
So, she has 3hrs to grade all papers, for 35 students.. alrite.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
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Given Equation:
Let us remove parenthesis first.
In order to remove parenthesis, we need to distribute -4 over parenthesis (2/3 h -3).
Distributing -4 over (2/3 h -3), we get,
-4*2/3 h - 4*-3 = -8/3 h + 12.
Substituting this value in original equation, we get
Now, in order to make the equation easy to solve, we always remove fractions. In order to remove fraction, we need to find the lowest common denominator of all terms(lcd).
The fraction terms has 3 in denominators, so we could multiply each and every term by 3 to remove 3's from denominators.
Multiplying each equation by 3, we get,
On simplfying this step, we get
Combining like terms on left side, we get
-7h +36 = 2h -18.
Subtracting 36 from both sides, we get
-7h +36 -36= 2h -18-36.
-7h=2h-54
Subtracting 2h from both sides, we get
-7h-2h=2h-54-2h
-9h = -54
Dividing both sides by -9.
-9h/-9 = -54/-9
h = 6.
Therefore, final answer is h=6.
Answer:
Step-by-step explanation:
Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:
Next we factor what we can so we can further simplify the rest of the equation:
We can now cancel out (x+2)
Next we factor out even more:
We cancel out x-4 and reduce the 3 and 6 into simpler terms:
And we can now simplify it to:
Answer:
a)
b)
c)
Step-by-step explanation:
Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.
To find : The following probabilities by summing the probabilities of the appropriate sample points ?
Solution :
The sample space is
S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}
n(S)=8
A: At least one head is observed
i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}
n(A)=7
B: At least two heads are observed
i.e. B={HHH,HTT,TTH,THT}
n(B)=4
C: The number of heads observed is odd.
i.e. C={HHH,HTT,THT,TTH}
n(c)=4
a) Probability of A, P(A)
b) P(A or B)
Using formula,
(c) P((not A) or B or (not C))
A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}
not A = {TTT} = 1
B={HHH,HTT,TTH,THT}
C={HHH,HTT,THT,TTH}
not C = {HHT,HTH,THH,TTT} = 4
So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5