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telo118 [61]
3 years ago
13

Reggie is planning to visit a clients office. He is taking a plane to get there, and the flight is scheduled to take five hours.

But the flight will be delayed by more than an hour because of bad weather. Reggie wants to call the airport hotel until the hotel manager when he will be arriving at the hotel. The variable X gives the elapsed time between ready schedule departure and his arrival at the hotel. Write an inequality for X, the time that passes between Reggie schedule departure in his arrival at the hotel.
Mathematics
2 answers:
Airida [17]3 years ago
8 0

Answer:

Reggie’s flight time is 5 hours and he expects a delay of more than an hour, so he should tell the manager to expect him at least 6 hours after his scheduled departure. The inequality is given by x > 6.

Step-by-step explanation:

ED menTUm ANSWERS

lilavasa [31]3 years ago
6 0

Answer: <em> x>6</em>

Step-by-step explanation:

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A study was conducted to determine if the salaries of elementary school teachers from two neighboring districts were equal. A sa
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Answer:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

(–2975, 175)

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Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Z_{1-\alpha /2} = Z_{0,975} = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values ​​differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

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