We are given: Function y=f(x).
First x-intercept of the y=f(x) is 2.
x-intercept is a point on x-axis, where y=0.
Replacing y by 0 and x by 2 in above function, we get
0=f(2)
Second x-intercept of the y=f(x) is 3.
Replacing y by 0 and x by 2 in above function, we get
0=f(3)
We are given another function y=8f(x).
Here only function f(x) is being multiplied with 8.
That is y values of function should be multiply by 8.
Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.
Therefore,
x-intercepts of y=8f(x) would remain same, that is 2 and 3.
Answer:
I think the answer is C
Step-by-step explanation:
The best way to do this is to make up values for the sides.
Say the lengths of square B's sides are each 4 cm. That means A's sides are 2 cm.
So, the area of square B is 4^2 = 16 cm^2, and A's area is 4 cm^2. We can see the shaded area is half of A, so it's 2 cm^2.
What percent of 16 is 2?
2 / 16 * 100 = 12.5%
C. f(x) = – 2 cos 6x + 1
Start by determining the amplitude. Since we've deduced the amplitude is 2, the equation can include either a positive or negative 2 (since amplitude measures absolute value).
Next is the period. The equation for period P is P = (2pi)/b. If P is pi/3, then
pi/3 = (2pi)/b. Thus your b value should be 6.
Finally, the midline would be given by + 1 since adding a unit shifts the function upwards. This means that instead of the highest y value being 2 and the lowest -2, instead you'd have values of 3 and -1.
(3 – 1)/2 = 1 (midpoint theory).
Answer:
The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92
Step-by-step explanation:
The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:
Denote the events as follows:
<em>X</em> = a students is a graduate
<em>Y </em>= a students is a under-graduate
+ = a student received one or more plus grades
- = a student received one or more minus grades
Consider the tree diagram below.
According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:
P (+ | Y) = 0.92
Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.
