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Likurg_2 [28]
2 years ago
8

Its a math problem Please help me !!! For the data sets below, which of the following statements is FALSE?

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
7 0

Answer:

fist bubble i am pretty sure

Step-by-step explanation:

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Let sin t = a​, cos t = b​, and tan t = c. Write the expression in terms of​ a, b, and c.
maks197457 [2]

Answer:

a+b-c

*Note c could be written as a/b

Step-by-step explanation:

-sin(-t - 8 π) + cos(-t - 2 π) + tan(-t - 5 π)

The identities I'm about to apply:

\sin(a-b)=\sin(a)\cos(b)-\sin(b)\cos(a)

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

Let's apply the difference identities to all three terms:

-[\sin(-t)\cos(8\pi)+\cos(-t)\sin(8\pi)]+[\cos(-t)\cos(2\pi)+\sin(-t)\sin(2\pi)]+\frac{\tan(-t)-\tan(5\pi)}{1+\tan(-t)\tan(5\pi)}

We are about to use that cos(even*pi) is 1 and sin(even*pi) is 0 so tan(odd*pi)=0:

-[\sin(-t)(1)+\cos(-t)(0)]+[\cos(-t)(1)+\sin(-t)(0)]+\frac{\tan(-t)-0}{1+\tan(-t)(0)

Cleaning up the algebra:

-[\sin(-t)]+[\cos(-t)]+\frac{\tan(-t)}{1}

Cleaning up more algebra:

-\sin(-t)+\cos(-t)+\tan(-t)

Applying that sine and tangent is odd while cosine is even.  That is,

sin(-x)=-sin(x) and tan(-x)=-tan(x) while cos(-x)=cos(x):

\sin(t)+\cos(t)-\tan(t)

Making the substitution the problem wanted us to:

a+b-c

Just for fun you could have wrote c as a/b too since tangent=sine/cosine.

8 0
3 years ago
Urgent please help! The high temperature in Garland dropped 3 degrees each day for five days straight. Which expression could NO
Montano1993 [528]

Answer:

First, see what is the temperature is on the first day before it dropped now on the fifth day see how much it drop from the first day to the last day hope this helped.

Step-by-step explanation:

7 0
3 years ago
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What digit is in the Hundred Thousand Place? 645,892
ASHA 777 [7]
The digit 6 is in the Hundred Thousand Place.
3 0
3 years ago
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Simplify the following expression as a<br> monomial:<br><br> -8a8<br> ———-<br> -2a7
Likurg_2 [28]

Answer:

4a

Step-by-step explanation:

-8 / -2 = 4

a^8/a^7 = a^(8 - 7) = a

Answer: 4a

8 0
2 years ago
How do u write 3:4 and 6:8 as a fraction proportion
faltersainse [42]

3/4=6/8

hope this helps :)

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