Answer:
23 over 3 ok my dear friends
Ur answer is
12.5
heres what helps me when im stuck hope it helps u =^-^=
pemdas steps
parentheses 1st
exponent 2nd
multiply 3rd
divide 4th
add 5th
subtract 6th
Answer:
u lookn hot tonight baby
Step-by-step explanation:
Answer:
The value of c in the equation c =6.
Step-by-step explanation:
In mathematics, a perfect square or a square number is an integer that is the square of an integer. In different words, it is the product of an integer with itself. For example, 9 is a square number because it can be written in 3 × 3.
The normal notation for the square of a number n is not the product n × n, but the equivalent exponentiation n2, which is generally pronounced as "n square". The square number of the name results from the name of the form. The unit area is defined as the area of a unit square (1 × 1). Consequently, a square of lateral length n has the area n2.
Square numbers are not negative. Another way to say that an integer (not negative) is a square is to make its square root an integer again.
For example, √9 = 3, so, 9 is a quadratic number.
A positive integer that has no perfect square divisors other than one is called without a square.
24.2² = 24.2 × 24.2 =585.64=abac.
From above equation, a=5,b=8,c=6.
Answer:
1)Mean=920 $
2)Standard Error =S.E.=38
3)more likely to take place Event 25 studio apartments with a mean rent between $901 and $939
Step-by-step explanation:
Given:
True mean =920 $
S.D=190 $
No .of samples=25
To Find:
1)Mean of sample.
2)S.E
Solution:
Now , the mean for given sample distribution is given as 920 $
Hence Mean =920 $
Now calculating the Standard error
S.E.= S.D./Sqrt(n)
=190/Sqrt(25)
=190/5
=38
Therefore the Standard error is about 38 .
a) When n=1 then P(901≤X≤939)
So,
Z1=(901 -920)/190/Sqrt(1)]
Z1=-0.1
Z2=(939-920)/(190/Sqrt(1)]
Z2=0.1
So
Pr(-0.1≤Z≤0.1)=P(Z≤0.1)-P(Z≤-0.1)
=0.5398-0.4602
=0.0797 % chance of the sample distribution
b)n=25 then P(901≤X≤939)
Z1=(901-920)/S.E
Z1=-19/38=
Z1=-0.5
And Z2=0.5
So,
Pr(-0.5≤Z≤0.5)
=Pr(Z≤0.5)-Pr(Z≤-0.5)
=0.6915-0.3085
=0.3829
i.e 38.29 % chance of the sample distribution
Hence More likely to take place will be a sample of 25 studio apartments with a mean rent between $901 and $939.
0.3829>0.0797.
Because the probability of causing above event is more than the option A.
