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2 years ago

What are the solutions of the quadratic equation?

Mathematics

2 answers:

Alik [6]2 years ago

7 0

Answer: D. x = 4 or x = -2

The correct answer is x = 4 or x = -2

Step-by-step explanation:

Hope this helps =)

Oliga [24]2 years ago

4 0

Answer:

d)X=4 or x=-2

Step-by-step explanation:

X²-2x=8

X²-2x-8=0

(x-4)(x+2)=0

X-4=0 or x+2=0

X=4 or x=-2

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3) Which ordered pair in the form (x, y) is a solution of this equation?<br> 7x - 5y = 1

Ludmilka [50]

(x,y) = (1, 1.2)
1 = 7(1) - 5(1.2)
1 = 7 - 6

There are many other options though.

3 0

3 years ago

Can anyone pls help me with this question ?

bagirrra123 [75]

Answer:

Step-by-step explanation:

When the function is less than but equal to and it's opposite are always solid dots. By this you can do simple process of elimination.

6 0

3 years ago

Solve for x:<br> 3/ X - 4 = 6/ X+1

Lina20 [59]

Answer:

-3/5

Step-by-step exp:

given in the file. Hope it helps.

8 0

3 years ago

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Maru [420]

A represents 12!
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8 0

3 years ago

A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

3 years ago