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3 years ago

How many five digit codes can be formed using digits 0 through 9?

Mathematics

1 answer:

ella [17]3 years ago

7 0

Answer:

100,000 combinations because if you have 5 digits, your equation is 10^5 which equals 100,000,

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Alejandra Plans to sew fringe on a scarf. The scarf is shaped like a rectangle. The length of the scarf is 48 inches. The width

tankabanditka [31]

Answer:

1152 inches of fringe

Step-by-step explanation:

l multiplies with width to get the area so

w is one half of 48 which 24

so 24x48 which is 1152 inches of fringe

5 0

3 years ago

in 2003 the population of zimbawe was about 12.6 million people wich is 1 million more than 4 times the population in1950.write

WITCHER [35]

12.6 million = 4p + 1 million
to solve:
12.6 million - 1 million = 4p + 1 million - 1 million
11.6 million/4 = 4p/4
2.9 million = p
the population in 1950 was approximately 2.6 million

8 0

3 years ago

I need help with 5,6,7 please

AlladinOne [14]

Answer:

see explanation

Step-by-step explanation:

the arc length of a circle is calculated as

arc = circumference of circle × fraction of circle

(5)

circumference (C) is calculated as

C = 2πr ( r is the radius )

here diameter = 12 , then r = 12 ÷ 2 = 6

C = 2π × 6 = 12π ≈ 37.7 m ( to the nearest tenth )

(6)

JK = 2πr × $\frac{75}{360}$

= 2π × 7 × $\frac{5}{24}$

= 14π × $\frac{5}{24}$

= $\frac{14\pi (5)}{24}$ ≈ 9.2 in ( to the nearest tenth )

(7)

7.5 = 2πr × $\frac{120}{360}$

7.5 = 2πr × $\frac{1}{3}$ ( multiply both sides by 3 to clear the fraction )

22.5 = 2πr ( divide both sides by 2π )

r = $\frac{22.5}{2\pi }$ ≈ 3.6 ft

7 0

2 years ago

796 sixth- eighth graders at CMS passed all classes for Q1 and get to be in Study Hall. If 80% of the CMS students are in Study

Hatshy [7]

I’ve found out that 80% of 796 is 636.8 and 20% of 796 is 159.2. i don’t know what else to do i’m sorry.

3 0

4 years ago

Suppose that D(r) is a function which gives the population density, in hundreds of people per square mile, within r miles of the

borishaifa [10]

Answer:

a) T(r) = r.D(r)

b) 975 people per square mile.

Step-by-step explanation:

(a)

The units of D(r) are

$\frac{hundreds\;of\;people}{mile^2}$

when multiplying the density by the area we get the amount of people in that area, so

$T(r)=rmile^2D(r)\frac{hundreds\;of\;people}{mile^2}=rD(r)\;hundreds\;of\;people$

(b)

The average rate of change of T(r) over the interval [5,7] is

$\frac{T(7)-T(5)}{7-5}=\frac{7D(7)-5D(5)}{2}$

but D(7) = 350 and D(5) = 100, so

$\frac{7D(7)-5D(5)}{2}=\frac{7*350-5*100}{2}=975$

and the average rate of change of T(r) over the interval [5,7] is 975 people per square mile.

5 0

4 years ago