Answer:
4
Step-by-step explanation:
To find the scale factor divide the new length by the original.
10/ 2.5 = 4
The scale factor is 4.
Answer:
Can I have the numbers???
Step-by-step explanation:
Given the two functions:
![\begin{gathered} R(x)=2\sqrt[]{x} \\ S(x)=\sqrt[]{x} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20R%28x%29%3D2%5Csqrt%5B%5D%7Bx%7D%20%5C%5C%20S%28x%29%3D%5Csqrt%5B%5D%7Bx%7D%20%5Cend%7Bgathered%7D)
We need to find (RoS)(4). THis is the functional composition. We take S(x) and put it into R(x) and then put "4" into that composed function. Shown below is the process:
![(RoS)(x)=2\sqrt[]{\sqrt[]{x}}](https://tex.z-dn.net/?f=%28RoS%29%28x%29%3D2%5Csqrt%5B%5D%7B%5Csqrt%5B%5D%7Bx%7D%7D)
When we plug in "4", into "x", we have:
Answer: Choice B. sqrt(2)
Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how
tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1
Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long
a^2 + b^2 = c^2
(1)^2 + (1)^2 = c^2
2 = c^2
c^2 = 2
c = sqrt(2)
The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with
sec(theta) = hypotenuse/adjacent
sec(theta) = AC/AB
sec(theta) = sqrt(2)/1
sec(theta) = sqrt(2) which is why choice B is the answer
600 is the answer ur welcome