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IrinaVladis [17]
3 years ago
14

Subtract -6 4 -6 0 6 4 - -5 5 -4 -1 6 -4

Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0
Do you mean, -6 - 4 - -6 - 0 - 6 - 4 - -5 - 5 - -4 - -1 - 6 - -4?

If so, here's my working out:
-6 - 4 = -10
-10 - -6 = -4
-4 - 0 = -4
-4 - 6 = -10
-10 - 4 = -14
-14 - -5 = -9
-9 - 5 = -14
-14 - -4 = -10
-10 - -1 = -9
-9 - 6 = -15
-15 - -4 = -11

The answer is -11.
Hope this helps!
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A bag contains 15 marbles. The probability of randomly selecting a green marble is 1/5. The probability of randomly
meriva

Answer:

2

Step-by-step explanation:

well if you get all of the fractions into percentage form they will be 20%for green 8% for blue so in turn it would mean 8% of 15 is 2

3 0
3 years ago
Let f(x) = 6x^2 + 5 and g(x) = 3x - 5. Find f(g(7)).
Vedmedyk [2.9K]

Answer:

D) 1541

Step-by-step explanation:

I like to answer it w without deriving the formula of f(g(x)). So, we go this way, you firstly have to find g(7) which will be equal to 3 * 7 - 5 = 16.

And then you find f(16) = 6*16*16+5 = 1541. That's all.

8 0
3 years ago
What is the volume of a cylinder whose circumfrence of 2 and heigth of 204?
True [87]
Volume = πr²h

circumference = 2πr = 2,   Height, h = 204

2πr = 2

πr = 2/2

πr = 1

r = 1/π

Volume = πr²h = π*(1/π)² * 204 = 204/π

Volume =  204/π   cubic length or ≈ 64.935 cubic length

I hope this helps.
8 0
4 years ago
Eduardo and Sarawong are selling wrapping paper for a school fundraiser. Eduardo sold 5 rolls of plain wrapping paper and 5 roll
Digiron [165]

Answer: A roll of plain wrapping paper costs $17, while a roll of holiday wrapping paper costs $20.

Step-by-step explanation: First let us represent a roll of plain wrapping paper with letter p and a roll of holiday wrapping paper would be represented by d. If Eduardo sold 5 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $185, then we can express this as

5p+ 5d= 185

Also if Sarawong sold 14 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $338, then this too can be expressed as

14p + 5d = 338

Now we have a pair of simultaneous equations which are,

5p + 5d = 185 ———(1)

14p + 5d = 338 ———(2)

Since all the variables have coefficients greater than 1, we shall use the elimination method. Note that the coefficients of the d variable are both 5, so straight away we subtract equation (1) from equation (2) and we now have;

(14p - 5p) + (5d - 5d) = 338 - 185

9p = 153

Divide both sides of the equation by 9

p = 17

Having calculated p, we can now substitute for the value of p into equation (1)

5p + 5d = 185

5(17) + 5d = 185

85 + 5d = 185

Subtract 85 from both sides of the equation

5d = 100

Divide both sides of the equation by 5

d = 20

Hence, the cost per roll of plain wrapping paper is $17, while the cost per roll of holiday wrapping paper is $20.

5 0
3 years ago
The theater sells two types of tickets: adult tickets for $15 and child tickets for $3. Last night, the theater sold a total of
Nuetrik [128]

Step-by-step explanation:

An adult ticket will be x.

Each adult ticket costs 15 dollars, so 15x

A child ticket will be y.

Each child ticket costs 3 dollars, so 3y

334 tickets were sold, totaling 3342 dollars.

15x + 3y = 3342 dollars in total.

Unknown number of adult tickets plus unknown number of child tickets equals to 334, so:

x number of adult tickets + y number of child tickets = 334 tickets in total.

x + y = 334

There are two equations in a system.

Use substitution:

x + y = 334

y = 334 - x

And plug it into other equation:

15x + 3(334 - x) = 3342

Solve for x since the question only asked for total number of adult tickets sold at theater (<em>remember x is the number of adult tickets</em>)

15x + (1002 - 3x) = 3342

15x + 1002 - 3x = 3342

Bring all x variables to one side and constants to other side:

15x - 3x = 3342 - 1002

12x = 2340

Divide both sides by 12:

x = 195

With that answer, we can conclude that 195 adult tickets were sold at the theater last night!

ANSWER: 195

3 0
3 years ago
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