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uranmaximum [27]
3 years ago
11

I need help finding the whole question, i'm not sure if what i've done already if correct, thanks

Mathematics
1 answer:
artcher [175]3 years ago
3 0
Median of 15

(14 + b) / 2 = 15
14 + b = 15 * 2
14 + b = 30
b = 30 - 14
b = 16

range of 30
 c - a = 30....c = 30 + a

mean of 18
(a + 8 + 14 + 16 + 26 + c) / 6 = 18
(a + 8 + 14 + 16 + 26 + (30 + a)) / 6 = 18
(2a + 94) / 6 = 18
2a + 94 = 18 * 6
2a + 94 = 108
2a = 108 - 94
2a = 14
a = 14/2
a = 7

c - a = 30
c - 7 = 30
c = 30 + 7
c = 37

check..
7,8,14,16,26,37
median = (16 + 14) / 2 = 30/2 = 15 ...correct
range = 37 - 7 = 30...correct
mean(average) = (7 + 8 + 14 + 16 + 26 + 37) / 6 = 108/6 = 18...correct

so a = 7, b = 16, and c = 37

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120%

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Which expression is a sum of cubes?
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we know that

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so

Let's verify each case to determine the solution

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we know that

-64=-4^{3}

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y^{12}= (y^{4})^{3}

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x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case A) is not a sum of cubes

<u>case B)</u> -32x^{6} y^{12} +125x^{16} y^{3}

we know that

-32=-2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case B) is not a sum of cubes

<u>case C)</u> 32x^{6} y^{12} +125x^{9} y^{3}

we know that

32=2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

therefore

the case C) is not a sum of cubes

<u>case A)</u> 64x^{6} y^{12} +125x^{9} y^{3}

we know that

64=4^{3}

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

Substitute

4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}

(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}

therefore

<u>the answer is</u>

64x^{6} y^{12} +125x^{9} y^{3} is a sum of cubes

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3 years ago
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schepotkina [342]

Answer:

the answer is 0.

Step-by-step explanation:

1/3(21) - 1 - 1/2(12) = 7 - 1 - 6 = 0

7 0
3 years ago
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Does anyone know how to do this?
uranmaximum [27]

Answer:

mRS = 116

Step-by-step explanation:

If Segment SR ≅ TU then, arc SR ≅ arc TU

Thus, 6x - 28 = 4x + 20

                       ^ ( note that this is the equation we will use to solve for x )

6x - 28 = 4x + 20  

step 1 add 28 to each side

28 + -28 cancels out

28 + 20 = 48

we now have 6x = 4x + 48

step 2 subtract 4x from each side

6x - 4x = 2x

4x - 4x cancels out

we now have 2x = 48

step 3 divide each side by 2

2x / 2 = x

48 / 2 = 24

we're left with x = 24

Now to find the value of arc RS we substitute x with 24 in arc RS' given expression

arc RS = 6x - 28

* substitute x with 24 *

arc RS = 6(24) - 28

6 * 24 = 144

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Answer:

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thus the cost function is

Cost=7000 m*$ /R + 50.265 $/m² * R²

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