Answer:
cost of the pool per cubic meters = $5
Step-by-step explanation:
The rectangular pool has a dimension of 30 m by 20 m by 2 m. To know the cost of the pool per cubic meter we have to calculate the volume of the pool . Then divide the total cost of the pool by it volume.
volume of the rectangular pool = length × height × width
volume of the rectangular pool = 30 × 20 × 2
volume of the rectangular pool = 1200 m²
The cost of installation is $6000 . The volume of the pool is 1200 cubic meters.
cost per cubic meters = total cost of installation/volume
cost per cubic meters = 6000/1200
cost of the pool per cubic meters = $5
A description of a dilation includes the scale factor (or ratio) and the center of the dilation. The center of dilation is a fixed point in the plane. If the scale factor is greater than 1, the image is an enlargement (a stretch). If the scale factor is between 0 and 1, the image is a reduction (a shrink
Answer:
$825.60
Step-by-step explanation:
Since the price of it is $960.00, it means that it's 100%.
100% = 960
1% = 960 ÷ 100 = 9.6
14% = 9.6 x 14 = 134.40
Since they asked for after the discount, deduct the price of the discount with the original price.
Mountain bike after 14% discount =
960 - 134.40 = 825.60
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
The first one would be C and the 2nd is A.
