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Aleonysh [2.5K]
3 years ago
9

(5y-3) 7 use the distributive property to rewrite each expression then simplify

Mathematics
1 answer:
Ilya [14]3 years ago
5 0
35y-21 would be the distributed expression
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The product of two numbers is 20. If one of the numbers is 5/14, what is the other number
Gnesinka [82]

Answer:

56 is the other number

Step-by-step explanation:

let the first number be a

the other number is 5/14 from the question

a x 5/14 = 20

5a/14 = 20

5a = 14  x 20 = 280

a = 280/5 = 56

5 0
3 years ago
Adidea Corp. estimates that $5,670 of its accounts receivables are uncollectible. How will the company record the transaction?
sergiy2304 [10]

Answer:

The transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

Step-by-step explanation:

Amount of money estimated = $5670

The amount which is non-collectible is recorded as a DEBIT transaction by the company because the amount in the non-collectible account can't be received by the company.

But, the amount in the receivables is the amount which is available for receiving and can be received by the company. So, receivable transaction is marked as CREDIT by the company.

Thus, the transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

4 0
3 years ago
Please help me understand and solve this​
ss7ja [257]

Step-by-step explanation:

just multiple them and you'll get the results and the results you got add them together

7 0
3 years ago
What is the coefficient of the first term in this expression? 6n³ + 4 + m<br><br>pls help<br>​
damaskus [11]

Answer:

The coefficient here is 6 because it is right beside the variable

Step-by-step explanation:

3 0
3 years ago
A study found that out of 300 people 60% of them prefer to eat hamburgers rather than hot dogs. Find the 95% confidence interval
Lerok [7]

Answer:

(0.5446, 0.6554)

Step-by-step explanation:

As the sample is sufficiently large, the formula is used to estimate the proportion shown in the attached image.

Where:

P: sample proportion = 0.6

n: Sample size = 300

1-\alpha: Confidence level = 0.95

α: Significance = 0.05

Z_{\alpha / 2} = 1.96 *

* Obtained from the normal standard table.

When introducing these values in the formula shown in the image we obtain:

0.6 + 1.96 *\sqrt {\frac{0.6*0.4}{300}}

0.6 - 1.96 *\sqrt{\frac{0.6*0.4}{300}}

Finally, the confidence interval is:

(0.5446, 0.6554)

8 0
3 years ago
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