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3 years ago

Braceleftzf y = 8/7 x − 2/3 8/3 x + y = 5/9

Mathematics

1 answer:

givi [52]3 years ago

7 0

Answer:

(x, y) = (77/240, -3/10)

Step-by-step explanation:

It is convenient to write the equations in standard form.

Multiplying the first equation by 21 gives ...

21y = 24x -14

Multiplying the second equation by 8 gives ...

24x +9y = 5

Then the system of equations in standard form is ...

24x -21y = 14
24x +9y = 5

Subtracting the first from the second, we get ...

(24x +9y) -(24x -21y) = (5) -(14)

30y = -9

y = -9/30 = -3/10

Substituting this into the second equation, we have ...

24x +9(-3/10) = 5

24x = 7.7 . . . . . . . add 27/10

x = 7.7/24 = 77/240

The solution is (x, y) = (77/240, -3/10).

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Answer:

$3.35

Step-by-step explanation:

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3 years ago

Mercury is a persistent and dispersive environmental contaminant found in many ecosystems around the world. When released as an

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Answer:

The sample mean is $\bar{x}=1.24$ and the sample median is 0.56

Step-by-step explanation:

The sample mean $\bar{x}$ of observations $x_1,x_2,...,x_n$ is given by

$\bar{x}=\frac{\sum x_i}{n}$

Applying the above definition we get that

The sum of these 15 sample observations is

$\sum x_i = 0.21+\:0.22+\:0.26+\:0.30+\:0.34+\:0.42\:+0.55+\:0.56+\:1.43+\:1.70+\:1.84+\:2.20+\:2.25+\:3.06+\:3.26\\\\\sum x_i =18.6$

and the sample mean is

$\bar{x}=\frac{18.6}{15}=1.24$

The sample median is obtained by first ordering the <em>n</em> observations from smallest to largest (with any repeated values included so that every sample observation appears in the ordered list). Then,

Sample median = The single middle value if n is odd = $(\frac{n+1}{2} )^{th}$

Sample median = The average of the two middle values if n is even = average of $(\frac{n}{2} )^{th}$ and $(\frac{n}{2}+1 )^{th}$

Applying the above definition we get that

The data is already ordered and n = 15 so,

Sample median = $(\frac{15+1}{2} )^{th}=8^{th}$ = 0.56

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3 years ago

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baherus [9]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

After mixing two types of candies, the price became $3.40 per lb. The quantity of the first type of candy was 5/12 of the quanti

Fynjy0 [20]

the price per pound of the second type of the candy is 2.9 .

<u>Step-by-step explanation:</u>

Here we have , After mixing two types of candies, the price became $3.40 per lb. The quantity of the first type of candy was 5/12 of the quantity of the second type. If the price of the first type of candy is $4.60 per lb,We need to find what is the price per pound of the second type of the candy . Let's find out:

The quantity of the first type of candy was 5/12 of the quantity of the second type i.e. Quantity of candy A = 5x quantity of candy B = 12x

We need to calculate the weighted average of the price of candies.

price of mixture = quantity of A (price of A ) + quantity of B (price of B)

⇒ $3.4(12x+5x)=12x(Price)+5x(4.6)$