The steps to use to construct a frequency distribution table using sturge’s approximation is as below.
<h3>How to construct a frequency distribution table?</h3>
The steps to construct a frequency distribution table using Sturge's approximation are as follows;
Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.
Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;
K = 1 + 3.322logN
where;
K= Number of classes
logN = Logarithm of the total number of observations.
Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size
Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.
Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.
Step 6; Distribute the data into respective classes:
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Answer:
Yes the answer is 4
Step-by-step explanation:
Answer:
J's would be (-5,-4) if J was reflected over the line x=3.
I believe the answer would be 4!
So 4 * 3 * 2 * 1
24.
Here's proof :
ABCD
ABDC
ACBD
ACDB
ADBC
ADCB
BACD
BADC
BCAD
BCDA
BDAC
BDCA
Following this order, each letter has 6 additional options, so 4! Would answer this appropriately. Some would say 6*4 but that's the same as 4*3*2 (3 and 2 becomes 6)
X= 5.1x+11.3
Explanation : combine like terms which is 5.1x and 3x and you get the answer D!
