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zhenek [66]
3 years ago
9

Find the integral, using techniques from this or the previous chapter. ∫x/25-9x^2 dx.

Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

Answer:

\frac{x^{2} }{50} - 3x^{3} +C

Step-by-step explanation:

we are to find the integral of  \frac{x}{25} -9x^{2} dx.

we will integrate by using the principle of integration of a sum or difference of two functions by integrating them separately.

∫x/25-9x^2 dx = \frac{x^{2} }{2*25}- 9\frac{x^{3} }{3} +C

                       = \frac{x^{2} }{50}- 3x^{3} +C

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Write a quadratic equation given the roots -1/3 and 5, show your work
Travka [436]

\boxed{(x - a)(x - b) = 0}

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

x =  -  \frac{1}{3}  \\ x = 5

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

(x +  \frac{1}{3} )(x -  5) = 0

Here we can convert the expression x+1/3 to this.

x +  \frac{1}{3}  = 0 \\  3x + 1 = 0

Rewrite the equation.

(3x + 1)(x - 5) = 0

Simplify by multiplying both expressions.

3 {x}^{2}  - 15x + x - 5 = 0 \\ 3 {x}^{2}  - 14x  - 5 = 0

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

3 {(5)}^{2}  - 14(5)  - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0

3( -  \frac{1}{3} )^{2}  - 14( -  \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) +  \frac{14}{3}  - 5 = 0 \\  \frac{1}{3}  +  \frac{14}{3}  -  \frac{15}{3}  = 0 \\  \frac{15}{3}  -  \frac{15}{3}  = 0 \\ 0 = 0

The equation is true for both roots.

<u>Answer</u>

\large \boxed {3 {x}^{2}  - 14x - 5 = 0}

8 0
3 years ago
Kyla makes a triangular school pennant. The area of the triangle is 180 square inches. The base of the pennant is z inches long.
kykrilka [37]
We can represent the base as z and the height as 2z+6. We are going to use the formula A=1/2*b*h and solve for z
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0=2(z^2+3z-180)
0=(z+15)(z-12)
So z=-15 and 12 but it must be positive so then the base is equal to 12

When we plug this into 2z+6 we get 30 for the height
2(12)+6=30

Hope this helps
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There are 7/8 kilograms of salt in the kitchen. Mrs. Jackson used 2/15 of salt when preparing dinner . How much salt did she use
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so since Mrs Jackson used 2/15 of 7/8, the amount she used is simply their product.


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