Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
Answer:
Step-by-step explanation:
Given:
ΔCAD and ΔCBD
∠A ≅∠B (Angle)
AD ≅BD (Side)
From the graph we see that
CD≅CD (Side)
because of reflexive propriety ( a line segment is congruent with itself)
If you put in order those congruencies we have SSA witch does NOT prove congruence.
we not use SAS because the angle between the sides is not congruent
-32 = 4c -12
add -34 by 12 which is -20
divide it by 4
c = -5
