All categories

4 years ago

What is a standard procedure for dividing by a two digit divisor explain

Mathematics

1 answer:

spin [16.1K]4 years ago

5 0

Long division, use math way

You might be interested in

Find the values of x and y <br> (no links or report don’t answer if u don’t know )

AleksAgata [21]

The x-axis is usually the horizontal axis, while the y-axis is the vertical axis. They are represented by two number lines that intersect perpendicularly at the origin, located at (0, 0), as shown in the figure below.

5 0

3 years ago

Does anybody know how to solve this ?

svetoff [14.1K]

Answer: ab

Step-by-step explanation:

4 0

3 years ago

FIRST GETS BRAINLEST __ Several tourists are participating in different

coldgirl [10]

Answer:

All you need to do is plot it on a graph. DO it from least to greatest and do it in order

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Suppose you roll 100 dice. What are the odds that 25 or more of them come up "6"?

Alex777 [14]

Answer:

1/6

Step-by-step explanation:

The probability of an event happening k times in n trials if the probability of the event is called p is the binomial distribution probability:

P(k times in n trials) = (Ckn)pk(1-p)n-k where the 1st term is the combination of n things k at a time or

n!/(k!(n-k)!)

In this case n is 100, k is 25 and P = 1/6

Hope that helps.

7 0

3 years ago

The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 < x

grandymaker [24]

Solution :

Given :

$f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.$

1. Cumulative distribution function

$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$

$=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx$

$=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$

$=\frac{1}{450} \int_6^x (x^2-x) \ dx$

$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$

$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right]$

$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$

2. Mean $E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$

$=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\ dx$

$=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$

$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$

$=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) - \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right)$

$=\frac{1}{450} [4608 - 252]$

= 17.2857

5 0

3 years ago