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3 years ago

Which answer best describes the shape of this distribution?

Mathematics

2 answers:

mestny [16]3 years ago

7 0

Skewed right is the answer

Goshia [24]3 years ago

5 0

I’m not quite sure what the answer is I’m sorry I can not help you maybe someone else can

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Evaluate: −9^4 A) −36 B) −6,561 C) 36 D) 6,561

Mrrafil [7]

It would be b)-6561 not the others

8 0

4 years ago

Free points: this is because of all the kindness I have seen on brainly:

const2013 [10]

Answer:

10x10= 100

Step-by-step explanation:

thx for the points

hope you have a wonderful dayyy

3 0

3 years ago

Read 2 more answers

-5.73q = 97.41 q= please help me???

jek_recluse [69]

First Divide both sides by -5.73

-5.73q/-5.73=97.41/-5.73

Answer: q=-17

7 0

3 years ago

I need the answers fast !!! this test is due today at 11:59

zhenek [66]

Answer:

Options 2 and 6

Step-by-step explanation:

Those are the locations of the points on the graph. If you look closely, you will see that it counts by twos.

5 0

3 years ago

Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0

3 years ago