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BigorU [14]
3 years ago
9

Which fraction is equivalent to StartFraction 2 Over 6 EndFraction?

Mathematics
1 answer:
Maru [420]3 years ago
3 0
Answer:
1/3
aka
StartFraction 1 over 3 EndFraction
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Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8
kherson [118]
<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323

</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323
3 0
2 years ago
What are the factors of 3x2 + 10x + 8?
vivado [14]

Answer: (3x+2)(x+4)

Step-by-step explanation:Explanation:

3x2+10x−8

first multiply

3

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and we get −24

then find two numbers that if we add or subtract we get

+10

and if we multiply we get

−24

and the numbers are

+12

and

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then we place those numbers as follow :-

3x2+12x−2x−8

then we group them

(3x2+12x)(−2x−8)

now take the common factor out.3x(x+4)−2(x+4)

then group the numbers outside of the brackets

(3x−2)(x+4)

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2 years ago
write 700/200 as a terminating decimal. then describe two methods for converting a mixed number to a decimal
zhuklara [117]
\frac{700}{200}=\frac{7}{2}\\\\\#1\\\frac{7}{2}=3\frac{1}{2}=3\frac{5}{10}=3.5\\\\\#2\\\frac{7}{2}=\frac{6+1}{2}=\frac{6}{2}+\frac{1}{2}=3+\frac{1}{2}=3+0.5=3.5\\\\\underline{0.5}\\1:2\\\underline{0}\\10\\\underline{10}\\R=0

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2 years ago
Carla needs to purchase carpet for her living room what is the area of carla's living room.
e-lub [12.9K]

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92 ft squared

Step-by-step explanation:

6*7=42

5*10=50

42+50=92 ft squared

3 0
3 years ago
Read 2 more answers
Hello please help me need aanswer​
Vika [28.1K]

\bold{\huge{\purple{\underline{ Answers :- }}}}

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

If I were one of the students in Barangay then I shall prepare the design of kite by using the known properties of kites in mathematics.

For example, Symmetrical about its main diagonals, Adjacent side equals, Having two pairs of congruent triangle etc.

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Design of kite assign to me

<u>Step </u><u>1</u><u> </u><u>:</u><u>-</u>

  • I shall take one paper and cut it like that the adjacent sides of paper are equal

<u>Reason </u><u>:</u><u>-</u>

  • <u>Adjacent </u><u>sides </u><u>of </u><u>kite </u><u>are </u><u>equal </u>

<u>Step </u><u>2</u><u> </u><u>:</u><u>-</u>

  • I shall take two thin sticks and paste it on the paper but sticks should intersect each other at 90°

<u>Reason</u><u> </u><u>:</u><u>-</u>

  • <u>Kite</u><u> </u><u>has </u><u>2</u><u> </u><u>diagonals </u><u>which </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u><u> </u><u>.</u>

<u>Step </u><u>3</u><u> </u><u>:</u><u>-</u>

  • <u>Make </u><u>a </u><u>hole </u><u>in </u><u>the </u><u>one </u><u>of </u><u>the </u><u>end </u><u>point </u><u>of </u><u>a </u><u>longest </u><u>sides</u><u>. </u>

<u>Observation </u><u>:</u><u>-</u>

  • <u>The </u><u>kite </u><u>should </u><u>be </u><u>looked </u><u>like </u><u>that </u><u>it </u><u>having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle</u><u> </u><u>with </u><u>common </u><u>base. </u>

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

  • The adjacent sides of the kites are equal that is 4cm and 6cm
  • The diagonals of the kite bisect each other at 90°
  • As kite is symmetrical from main diagonals , so it has two opposite and equal Angles that is 127°
  • The opposite angles at the end points of kite are congruent that is Angle D and Angle C
  • AC is the bisector of AB and AB is the bisector of AC .

[ Note :- Kindly refer the above attachment ]

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

All mathematical concepts used in making kite are as follows :-

  • <u>Adjacent </u><u>sides </u><u>are </u><u>equal </u>
  • <u>Diagonal </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>
  • <u>Having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle </u><u>with </u><u>common </u><u>base </u>
  • <u>Symmetrical </u><u>about</u><u> </u><u>its </u><u>main </u><u>diagonal</u>
  • <u>Opposite </u><u>angles </u><u>at </u><u>the </u><u>end </u><u>points </u><u>are </u><u>equal</u>

3 0
2 years ago
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