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RSB [31]
3 years ago
10

What is 1/3 off of $449.55? (Please show work)

Mathematics
2 answers:
lidiya [134]3 years ago
8 0
449.55 x .333 = 149.70 if rounded from 149.70015 449.55 - 149.70 = 299.85
balu736 [363]3 years ago
6 0
449.55 divided by 1/3 is $<span>149.85 
 
the answer is $149.85

here to help :)</span>
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I need helpp will give brainliesst!!!
Irina18 [472]

Answer:

C) 7c+6s-63

Step-by-step explanation:

set up this equation because you are adding the two expressions

7c-18+6s-45

combine like terms

7c+6s-63

4 0
3 years ago
The area of the poster is (x^2+2x-15) inches the width is (x-3) inches calculate the dimensions of the poster board when x=14
givi [52]

Answer:

The poster is 11 inches wide and 19 inches in height.

Step-by-step explanation:

We take the given equation: (x^2+2x-15) and we add in 14 as our x variable:

((14)^2+2(14)-15) the answer we get from that is 209. The area of the poster is 209 square inches. Then we find the width by taking (x-3) in this case x is 14 so the width of the poster is 11. In order to find the height we divide the height by the width and we get 19.

Therefore:

Height= 19 Inches

Width= 11 Inches

Total Area= 209 Square Inches

4 0
3 years ago
Can someone help me and explain how to do it.
skelet666 [1.2K]

Answer:

uhhhhhhh you have to figure out what x is then choose wether it is the other variable a dependent variable, and explanatory variable, or a response variable

Step-by-step explanation:

easy as that

4 0
3 years ago
Evaluate the following functions at x = 10 q(x)=x^2-2x+2​
Oduvanchick [21]

Answer:

82

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

=80+2

=82

Pls mark me brainliest

5 0
3 years ago
Name a point that is between 50 and 60 units away from (7,-2) and state the distance between the two points.
laila [671]

Let the required point be (a,b)

The distance of (a,b) from (7,-2) is

= \sqrt{(a-7)^2+(b+2)^2}

But this distance needs to be betweem 50 & 60

So

50

Squaring all sides

2500 < (a-7)² + (b+2)² < 3600

Let a = 7

So we have

2500 < (b+2)² <3600

b+2 < 60    or  b+2 > -60   => b <58 or b > -62

Also

b+2 >50    or b + 2 < -50  => b >48 or B < -52

Let us take one value of b < 58 say b = 50

So now we have the point as (7, 50)

The other point is (7,-2)

Distance between them

= \sqrt{(7-7)^2+(50+2)^2}= \sqrt{(52)^2}=52

This is between 50 & 60

Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)


6 0
3 years ago
Read 2 more answers
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