Answer:
C) 7c+6s-63
Step-by-step explanation:
set up this equation because you are adding the two expressions

combine like terms

Answer:
The poster is 11 inches wide and 19 inches in height.
Step-by-step explanation:
We take the given equation: (x^2+2x-15) and we add in 14 as our x variable:
((14)^2+2(14)-15) the answer we get from that is 209. The area of the poster is 209 square inches. Then we find the width by taking (x-3) in this case x is 14 so the width of the poster is 11. In order to find the height we divide the height by the width and we get 19.
Therefore:
Height= 19 Inches
Width= 11 Inches
Total Area= 209 Square Inches
Answer:
uhhhhhhh you have to figure out what x is then choose wether it is the other variable a dependent variable, and explanatory variable, or a response variable
Step-by-step explanation:
easy as that
Answer:
82
Step-by-step explanation:
given:x=10
Evaluating,
(10)²-2(10)+2
=100-20+2
=80+2
=82
Pls mark me brainliest
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So

Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)