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aniked [119]
3 years ago
9

Simplify the expression.(1 − 6i) + (5 + i)​

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0

Answer:

6-5i

Step-by-step explanation:

To solve for this equations we have to group the like terms together

(1-6i)+(5+i)

we will group -6i with +i  and positive 1 with positive 5

so we get (-6i+i)+(1+5)

                  -5i+6   or can be written as 6-5i          

    -6i+i ( there is actually an imaginary 1 with i and you subtract these 2 numbers because the signs are different and use the signs of the larger number which is 6 and the sign is negative.

kvasek [131]3 years ago
4 0

Answer:

6+-5i

or

6-5i

Step-by-step explanation:

(1-6i)+(5+i)

We do not need the ( ) since the operation is just addition.

1-6i+5+i

Reorder using commutative property so that like terms are together:

1+5+-6i+i

Use multiplicative identity property:

1+5+-6i+1i

Simplify:

6+-5i

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mario62 [17]

Answer:

The equation of parabola is standard form is x=\left(y+4\right)^2+2

Step-by-step explanation:

Given equation of parabola is,

y^2+8y-x+18=0

In order to find the equation of parabola in standard form, eliminate x from left side of equation and use completing square method to find the equation.

First step is to add x on both side of equation.

y^2+8y-x+18+x=0+x

y^2+8y+18=x

Rewriting,

x=y^2+8y+18

Now applying completing square method as follows.

Following are the steps for calculation of this method.

Find the last term of above equation by using below formula,

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Now coefficient of y is 8.

\therefore Last\:term\:of\:square=\left(\dfrac{8}{2}\right)^{2}

Simplifying,

Last\:term\:of\:square=\left(4\right)^{2}

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Second step is to add and subtract the last term.

x=y^2+8y+18+16-16

Rewriting,

x=y^2+8y+16+18-16

Since \left(a+b\right)^{2}=a^{2}+2ab+b^{2}

Using above formula,

x=\left(y+4\right)^{2}+2

Therefore, the equation of parabola in standard form is x=\left(y+4\right)^{2}+2

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