If the base were 1, then the final value would never change...it would be a constant...
If the base is between zero and one, it is an exponential decay equation, so the final value would continually get smaller and smaller...
N³ - 2n² - 15n = 0
"n"
n (n² + 2n - 15) = 0
n = 0
n² + 2n - 15 = 0
Δ = (2)² - 4(1)(-15)
Δ = 4 + 60 = 64
n' = (-2+8) / 2 = 6/2 =3
n'' = (-2-8) / 2 = -10/2 = -5
Solution:
S {-5 , 0 , 3 }
Answer:
the last one
Step-by-step explanation:
Answer:
It is 3 square root of 7
Step-by-step explanation:
:)
