The question containing the steps is missing.
Answer:
m∠M = 79°
m∠N = 66°
Step-by-step explanation:
∠MPN is supplementary to ∠MPQ, so m∠MPN = 35
The sum of the measures of a triangle is 180.
So, m∠M + m∠N + m∠MPN = 180
5y + 4 + 4y + 6 + 35 = 180
9y + 45 = 180
9y = 135
y = 15
m∠M = 5y + 4 = 5(15) + 4 = 75 + 4 = 79
m∠N = 4y + 6 = 4(15) + 6 = 66
Another way to do this problem, which is easier, is to know that an exterior angle of a triangle is equal to the sum of the two remote interior angles.
That means 5y + 4 + 4y + 6 = 145
9y + 10 = 145
9y = 135
y = 15
From knowing the value of y you can now find the measures of angles M and N
Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
Answer:
they can be lined up from front,side, back
Step-by-step explanation:
if u line them by side their in a straight line and hips faced to camera,or smallest to tallest in face front camera or back point of view in jumping, or holding hands.
