I have an average of 84 right now but I failed my homework so that would most likely turn to an 82 and my parents will actually
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Given:
The limit problem is:
To find:
The value of the given limit problem.
Solution:
We have,
In the function , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
Therefore, .
3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 =
/6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7/6
360-3=330 = 11/6
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 =
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7
360-3=330 = 11