On a coordinate plane, triangle A B C is shifted 4 units to the right and 2 units up to form triangle A prime B prime C prime. I dentify the rule for the transformation shown in the figure that translates triangle ABC into triangle A'B'C'. (x, y) Right-arrow (x – 4, y – 2) (x, y) Right-arrow (x + 4, y – 2) (x, y) Right-arrow (x – 4, y + 2) (x, y) Right-arrow (x + 4, y + 2)
1 answer:
Answer:
(x, y) ⟶ (x + 4, y + 2)
Step-by-step explanation:
If you shift a point four units to the right, x ⟶ x + 4.
If you shift it up two units, y ⟶ y + 2 .
If you combine the two shifts into one transformation, the rule becomes
(x, y) ⟶ (x + 4, y + 2)
You might be interested in
Answer:
1) first two (A & B)
2. -1,533
Step-by-step explanation:
Sum to infinity is finite when
-1 < r < 1
Option 1: r = -¼
Option 2: r = 27/81 = ⅓
Option 3: r = 3/2
Option 4: r = 17.75/7.1 = 2.5
a = -3
r = -6/-3 = 2
S9 = -3 × (2⁹ - 1)/(2 - 1)
= -1533
Answer:
answer is B because in the property of parallelogram it says ad is parallel to bc
Answer:
x=6
Step-by-step explanation:
work is shown in picture
Answer:
Step-by-step explanation:
we are given
Amplitude:7 Period:9π Phrase shift:¼ remember that,
where A is the Amplitude
B is the Period
C is the Phase shift
D is the vertical shift
note that, since D isn't given we'll take it 0
altogether substitute:
hence,
our equation is
and we are done!
Answer:
2y = x+6
Step-by-step explanation:
From (y-1) = -2(x-1)
y-1 = -2x+2
y=-2x+2+1
y=-2x+3 compare with y = mx +C
m1= -2
For perpendicularity rule: m1m2 = -1
m2 = -1/-2 = 1/2
Equation of the line that passes through (0,3) is
y-y1 = m2(x-x2)
y-3 = 1/2(x-0) = 1/2(x)
y-3 = x/2
Multiply through by 2
2y-6 = x
2y = x+6
2y-x=6
2y-x-6=0