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3 years ago

What is a perimeter of a rectangle if one side is 6 in. and one is 8 in.?

Mathematics

2 answers:

ohaa [14]3 years ago

5 0

Answer:

Step-by-step explanation:

6+6+8+8. Opposite sides of a rectangle are congruent

sergiy2304 [10]3 years ago

3 0

Answer: 28

Step-by-step explanation: 6+8+6+8=28

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Write the product of 7 and a number w as an expression.<br><br> what's the answer?

olga55 [171]

The expression is 7w

3 0

3 years ago

Solve the equation for a.

Pavel [41]

Answer:

$\large\boxed{a=\dfrac{K}{4+9b}}$

Step-by-step explanation:

$K=4a+9ab\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\K=a(4+9b)\qquad\text{divide both sides by}\ (4+9b)\neq0\\\\\dfrac{K}{(4+9b)}=\dfrac{a(4+9b)}{(4+9b)}\\\\\dfrac{K}{4+9b}=a$

6 0

3 years ago

Read 2 more answers

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

I used 2/3 for tickits and 1/6 on popcorn how much money is left

posledela

Answer:

You would have 1/6 of your money remaining.

Step-by-step explanation:

Let's write an equation for this.

1 - (2/3 + 1/6)

First, let's multiply the numerator and denominator of 2/3. You get 4/6!

1 - (2/3 + 1/6)

1 - (4/6 + 1/6)

Next, let's add 4/6 and 1/6. You get 5/6!

1 - (4/6 + 1/6)

1 - 5/6

Finally, let's turn 1 into 6/6 and do 6/6 - 5/6!

1 - 5/6

6/6 - 5/6

1/6

You would have 1/6 of your money remaining.

3 0

2 years ago

A trapezoid has an area of 50 square inches.

Shalnov [3]

The area of a trapezoid can be computed as:

A=(b1+b2)h/2, where b1 and b2 ar the bases, h is the height.

With the provided numerical values:

50=(3+7)h/2

50=10h/2=5h

Answer: h=10inches

4 0

3 years ago