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e-lub [12.9K]
2 years ago
13

Plz help meUse the table chart and find out what the alitude of 5,000 feet.

Mathematics
1 answer:
mash [69]2 years ago
6 0
The is (5000,59) and you can check this by doing this -0.004(5000)+79
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If (x, y) is a solution to the system of equations, what is the value of x?
GREYUIT [131]

Answer:

B) -4

Step-by-step explanation:

(5/2)x + y = 2

x + (2/3)y = 4

y = 2 - (5/2)x

x + (2/3)(2 - (5/2)x) = 4

x + 4/3 - (5/3)x = 4

(-2/3)x = 8/3

-2x = 8

x = -4

3 0
3 years ago
How to solve this problem?
777dan777 [17]

Answer:

Can not be determined.

Step-by-step explanation:

We can easily notice that the limit is x tends to infinity, whereas x is not present in the given function, we are given (1 + 1/n). So we can not evaluate the given limit for x as parameter, we must have some function of x to solve this problem.

Hence, option C is correct i.e. the limit can not be determined.

5 0
3 years ago
I need help!! I'll report if wrong ​
ss7ja [257]

Answer:

23

Step-by-step explanation:

2+2+3+4+5+6 = 23

3 0
2 years ago
A store buys calculators for $5 and sells them at a markup of 350%. One day, they decide to put the calculators on sale and mark
Grace [21]

Answer:

Option D

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.
aleksandr82 [10.1K]

Answer:

The probability is 0.508 = 50.8%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.

This means that \mu = 0.8544, \sigma = 0.0525

If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g.

This is 1 subtracted by the pvalue of Z when X = 0.8535. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.8535 - 0.8544}{0.0525}

Z = -0.02

Z = -0.02 has a pvalue of 0.492

1 - 0.492 = 0.508

The probability is 0.508 = 50.8%.

8 0
3 years ago
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