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Inessa [10]
2 years ago
11

Please help!

Mathematics
1 answer:
ella [17]2 years ago
7 0

Answer:

y = x + 5          

Step-by-step explanation:

1) First, find the slope of the line x-y = 4. We can do this by setting it up in slope-intercept form, represented by the equation y = mx + b. Whatever m or the coefficient of the x-term is will be the slope. Isolate y in the equation:

x-y = 4\\-y = -x+4\\y = x -4

So, the slope of the given equation is 1. Parallel lines share the same slope, thus the slope of the new line will be 1 as well.

2) Now, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 in the formula.

Since m is the slope, substitute 1 for it. Since x_1 and y_1 represent the x and y values of one point the line passes through, substitute the x and y values of (-6, -1) into those places as well. Then, isolate y in the resulting equation to put the equation in slope-intercept form and find the answer:  

y-(-1) = 1 (x-(-6))\\y + 1 = 1 (x + 6)\\y + 1 = x + 6\\y = x + 5

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n + n^2 = 72

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You must check both answers before accepting one, the other or both.

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Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

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From the question,

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d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

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