Answer:
Step-by-step explanation:

Answer:
Step-by-step explanation: (9=4-38-838,256=2-60^7
(1) Looks like the joint density is

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is


(2) The region in which <em>X</em> > 2 and <em>Y</em> < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

(3) Are you supposed to find the marginal density of <em>X</em>, or the conditional density of <em>X</em> given <em>Y</em>?
In the first case, you simply integrate the joint density with respect to <em>y</em>:

In the second case, we instead first find the marginal density of <em>Y</em>:

Then use the marginal density to compute the conditional density of <em>X</em> given <em>Y</em>:

V1=60. 60×t1=50×t2=S
V2=50
T=t1+t2=5. 5-t2=t1
60×(5-t2)=50×t2
300-60×t2=50×t2
300=50×t2+60×t2
300=t2×(50+60)
300=t2×110
300/110=t2
S=50×300/110