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allochka39001 [22]
4 years ago
5

Brook states that the distance on the line is 4 units. Caleb states that the whole line does not have a distance because it cont

inues on forever. Vivian states that the line is 6 units long.

Mathematics
2 answers:
Reika [66]4 years ago
6 0
The answer would be that Brook measured the distance between L and M
Radda [10]4 years ago
5 0
Brook did the distance between L and M, Vivian however did the distance between M and N. Hope this helps you
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What linear equation is represented by the table? 1
rewona [7]

Answer:

Y=4x-2

Step-by-step explanation:

You have to try it (x,y) (2,6)

y=4x-2

6=4(2)-2

6=8-2

8 0
3 years ago
From least to greatest would this be right or do I have to change it?<br><br> 177,156,99,87
harina [27]

Answer:

From least to greatest it would be 87, 99, 156, 177

Step-by-step explanation:

The statement "from least to greatest" means starting from the lowest value and transitioning to the greatest value/

Think of it as least -> greatest.

3 0
3 years ago
Researchers surveyed 250 college students at one time. They were asked if they were taking any engineering classes and whether o
Setler [38]

Answer:

the  incidence of the depression is  1 ÷ 5

Step-by-step explanation:

Given that

There is 250 college students that are surveyed

In the case when 75 students reported for minimum ne engineering class

And, out of this 15 students would be depressed

We need to find out the incidence of the depression

So

= 15 ÷ 75

= 1 ÷ 5

Hence, the  incidence of the depression is  1 ÷ 5

8 0
3 years ago
Which ordered pair in the form (a, b) is a solution of this equation?
Evgen [1.6K]

3a - 4b = 21


check (-2 , -3)


3(-2) -4(-3) =21


-6 +12  = 21


6 does not = 21  so NO


check (0 , 7)


3(0) -4(7) =21


0-28=21


-28 does not equal 21  so NO


check (-3 , -2)


3(-3) -4(-2) =21


-9 +8  = 21


1 does not = 21  so NO


check (7 , 0)


3(7) -4(0) =21


21  = 21

Choice D

5 0
4 years ago
Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ
irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).

Then after solving, it become and with theorem it says that the

\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

brainly.com/question/15409558

#SPJ4

3 0
2 years ago
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