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Mekhanik [1.2K]
3 years ago
13

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

nd asymptotes. See Example 6.
y = ln 5x/x^2

Mathematics
1 answer:
Anit [1.1K]3 years ago
4 0

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given y=\frac{\ln\left(5x)}{x^2}

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

y'=\frac{1-2\ln\left(5x)}{x^3}=0

x = \sqrt e/5 is absolute maximum

y''=\frac{6\ln\left(5x)-5}{x^4}=0

x=e^{5/6}/5 is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

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If i= V-1, then which expression is equal to 9i(13i)?<br>F -117<br>H 117<br>G 117i<br>I -117i​
DaniilM [7]

If i= V-1, then -117 expression is equal to 9i(13i)

Step-by-step explanation:

Original problem : 9i(13i)

=> 117i^{2} (Multiply)

=> 117 * -1

=> i^{2} = -1

=> -117

If i= V-1, then -117 expression is equal to 9i(13i)

3 0
4 years ago
The point-slope form of the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard f
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Multiply by 4 and rearrange.

... 4y -4 = x - 12

... -4 = x - 4y - 12 . . . . . . subtract 4y

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5 0
3 years ago
Read 2 more answers
What value of y will make the equation true?
xenn [34]

Generally the value of y would be 34 because same two square roots of n multiplying each others would equal to n by the definition.

\large \boxed{ \sqrt{a}  \times  \sqrt{a}  = ( \sqrt{a} )^{2}  = a}

Although it is easy to predict the solution of y-value, I will be showing you how to solve the radical equation for y-term which will be useful.

\large \boxed{ \sqrt{a}  \times  \sqrt{b}  =  \sqrt{ab} }

So from the equation, convert √34 × √y to √34y

\large{ \sqrt{34}  \times  \sqrt{y}  = 34} \\  \large{ \sqrt{34y}  = 34}

Then we square both sides to get rid of the square root.

\large{ {( \sqrt{34y} )}^{2}  =  {34}^{2} } \\  \large{34y = 1156}

Divide both sides by 34 so we can finally isolate the y-term.

\large{ \frac{34y}{34}  =  \frac{1156}{34} } \\  \large \boxed{y = 34}

Hence the value of y is 34.

Answer

  • y = 34

7 0
3 years ago
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