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soldi70 [24.7K]
3 years ago
5

Guys pls help me!!!!!!

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

C hope this help you

agasfer [191]3 years ago
4 0

Answer:

B

Step-by-step explanation:

If x is any larger than 4 it would be greater than 5, since 2*4-3=5

If x was any smaller than -1  it would be greater than 5, since 2*-1-3=|-5|=5

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Answer:

Step-by-step explanation:

Here's how you convert:

\sqrt[n]{x^m}=x^{\frac{m}{n}  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

\sqrt[3]{x^4}=x^{\frac{4}{3}

\sqrt[5]{x^7}=x^{\frac{7}{5}

It's that simple. For your problem in particular:

\sqrt[3]{7} is the exact same thing as \sqrt[3]{7^1}=7^{\frac{1}{3}

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