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valentina_108 [34]
3 years ago
9

Please I needa answer !!

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

the answer is B and C

Step-by-step explanation:

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Ms. Stevens gave a 30 question quiz to her Algebra 1 class. After grading the quizzes, her students received the following score
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For what value of x is the rational expression below undefined?
Blizzard [7]

Answer: The expression is undefined for x=4 and x=5.

The expression is undefined for any x that makes the denominator 0. This leads to solving a quadratic equation:

\frac{x+3}{x^2-9x+20}\\x^2-9x+20\neq 0\\x_{1,2}\neq\frac{9\pm\sqrt{9^2-80}}{2}=\frac{9\pm1}{2}\\x_1\neq4\\x_2\neq5

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3 years ago
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The area of a circle is 16pi cm2. What is the circle's circumstance?
gavmur [86]
I think you mean circumference...Area is A= \pi  r^{2}. We have the area so we need to use it to solve for the radius which we will then use in the circumference formula.  16 \pi = \pi  r^{2}.  Divide both sides by pi to get \frac{16 \pi }{ \pi } = r^{2}.  Of course the simplification of the left side gives us 16= r^{2} and r = 4.  Now fill that in to the circumference formula, which is C=2 \pi r, to get CC=2 \pi (4) which is a circumference of 8 \pi
4 0
3 years ago
A skyrocket is launched from a 30–foot-high platform, with initial speed 300 ft/s. If the polynomial −16t2 + 300t + 30 gives the
Stella [2.4K]

Answer:

566 ft

Step-by-step explanation:

Given the polynomial equation

-16t² + 300t + 30 = 0

We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have

-16 * 2² + 300 * 2 + 30

-16 * 4 + 600 + 30

-64 + 630 = 566 ft

Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft

8 0
3 years ago
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

\Delta f = 3

(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)

\Delta f = 3

Both sequences are arithmetic.

8 0
2 years ago
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