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gladu [14]
3 years ago
10

A blank is a common multiple of two or more demominators

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0
A prime number witch meansit hase more than 2 multiples other than 0 and 1 or its self

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How many solutions does the system have?
RUDIKE [14]

For this case we have the following system of equations:

21x + 6y = 42\\7x + 2y = 14

We multiply the second equation by -3:

-21x-6y = -42

Thus, we observe that the second equation is equivalent to the first, if we add both we get:

21x-21x + 6y-6y = 42-42\\0 = 0

The equality is fulfilled. The lines are on top of each other.

Answer:

Infinite solutions

6 0
3 years ago
Read 2 more answers
The triangles shown below must be congruent.<br> O True<br> O False
sertanlavr [38]

Answer:

The answer to the problem is True

7 0
2 years ago
Abby did 121 sit ups in 8 minutes estimate the number of sit ups she did in 1 minute
const2013 [10]
You would divide 121 by 8.
121 / 8 =  15.125 So she did about 15 sit ups in a minute. Hope this helps!
 
4 0
3 years ago
Read 2 more answers
Factor -7x3 + 21x2 + 3x - 9 by grouping. What is the resulting expression?
irga5000 [103]

Answer:

(x-3)(-7x^2+3) is the resulting expression after grouping

Step-by-step explanation:

Given:

-7x^3+21x^2+3x-9

Now taking common -7x^2 from 1st 2 numbers and and 3 common from last we get

-7x^2(x-3)+3(x-3)

Now taking x-3 common from both numbers we get

(x-3)(-7x^2+3) which is the final equation after grouping

8 0
3 years ago
H E L P M E P L E A S E !!!
Art [367]

Given:

The table of data values.

To find:

What is the percentage of 10th grade students are in 2 clubs.

Solution:

From the given table it is clear that the number of 10th grade students are in 2 clubs is 12.

Total number of students in 10th grade is:

125+12+15=152

Now, the percentage of 10th grade students are in 2 clubs is:

\text{Required percentage}=\dfrac{\text{Number of 10th grade students are in 2 clubs}}{\text{Total number of students in 10th grade}}\times 100

\text{Required percentage}=\dfrac{12}{152}\times 100

\text{Required percentage}=\dfrac{1200}{152}

\text{Required percentage}\approx 7.89\%

Therefore, the percentage of 10th grade students are in 2 clubs is 7.89%.

5 0
3 years ago
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