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VashaNatasha [74]
2 years ago
11

How to solve for exponent using PEMDAS​

Mathematics
1 answer:
sammy [17]2 years ago
4 0

Answer:

In PEMDAS the E stands for exponents so if you see a problem with exponents and there is no parentheses you would just do exponents first.

Step-by-step explanation:

PLZ MARK BRAINLIEST if not that's fine (:

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How many blocks are needed for the 5th example?​
JulsSmile [24]

Answer:

5th example: 28 blocks.

24th example: 123 blocks.

Step-by-step explanation:

Hope this helped!

7 0
2 years ago
You need to get to class, 200 meters away, and you can only walk in the hallways at about 1.5 m/s. (if you run any faster, you’l
RUDIKE [14]

Answer:

Time = 133.3 secs

Step-by-step explanation:

<u><em>Speed = Distance / Time</em></u>

<em>Rearranging the formula</em>

Time = Distance / Speed

Where D = 200 m , S = 1.5 m/s

Time = 200 / 1.5

Time = 133.3 secs

6 0
3 years ago
Read 2 more answers
guys pls i post two more questions that i dont kno and i want to pass my test sorry ,but they are important
Andrej [43]
Okkk .. this is what this app is for anyways to help.
5 0
3 years ago
I've got a math test wish me luck​
kaheart [24]

Step-by-step explanation:

best of luck dear.........

6 0
3 years ago
You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the
natita [175]

Answer:

In the first account was invested \$3,000  at 3%

In the second account was invested \$4,000  at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

First account

t=1 years\\ P=\$x\\ r=0.03

substitute in the formula above

I=x(0.03*1)

I=0.03x

Second account

t=1 years\\ P=\$(7,000-x)\\ r=0.05

substitute in the formula above

I=(7,000-x)(0.05*1)

I=350-0.05x

Remember that

The interest is equal to \$290

so

Adds the interest of both accounts

0.03x+350-0.05x=\$290

0.05x-0.03x=350-290

0.02x=60

x=\$3,000

therefore

In the first account was invested \$3,000  at 3%

In the second account was invested \$7,000-\$3,000=\$4,000  at 5%

7 0
3 years ago
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