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Zigmanuir [339]

3 years ago

13

The current value Of a investment is 25% More than its initial value the increase in value is 10million what was the initial val

ue of investment

1 answer:

azamat3 years ago

8 0

Answer:

50 million

Step-by-step explanation:

current value: c

initial value : i

c = 1.2 × i

x - i = 10

10 + i = 1.2 × i

0.2 ×i = 10

i = 50

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Rita offers to pay for 8 of her friends to play lazer tag, but 3 of them dont want to pay

Mrac [35]

Answer:

only 5 of her friends will play

Step-by-step explanation:

8-3=5

6 0

3 years ago

Read 2 more answers

Which factor or factors listed below are internal influences on a loans interest rate?

Feliz [49]

<span>Each of the following lines from "The Love Song of J. Alfred Prufrock" contains allusion except
A. "I am no prophet—and here's no great matter;"
B. "To say: I am Lazarus, come from the dead,"
C. "No! I am not Prince Hamlet, nor was meant to be;"
D. "I shall wear white flannel trousers, and walk upon the beach."
Read the following lines from "The Love Song of J. Alfred Prufrock." </span>

5 0

3 years ago

Eli is making a party mix that contains pretzels and chex. For each cup of pretzels, he uses 3 cups of chex. He wants to make 12

Bogdan [553]

Answer:

36 cups of Chex total.

Step-by-step explanation:

Well, he will obviously be using 12 cups of pretzels, so let's set that aside. For every cup of pretzels, there are 3 cups of chex. So, multiply 3x12. That will give you how much chex you will need.

4 0

3 years ago

Please help me!<br> Find the number x such that f(x) =1

STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

3 years ago

Plz help it’s very confusing

zepelin [54]

So the total is 120. You want 1/6 of those.
So do (1/6)*120
You get 20.

YAY

6 0

3 years ago