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3 years ago

Solve the formula c = pi d for d

Mathematics

2 answers:

serious [3.7K]3 years ago

8 0

Answer is B
Hope it’s right

STALIN [3.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

We want to solve for d.

Our given equation is C = πd, where π and d are multiplied together.

In order to solve for d, we need to isolate it; in other words, we need to move the π to the left side with C. To do so, we must "undo" the multiplication; and what's the "undo" for multiplication? It's just division.

Thus, we simply divide both sides by π to get:

d = C/π

Our answer is thus B.

~ an aesthetics lover

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Alex17521 [72]

Step-by-step explanation:

Let the equation of the line be y = mx + c

since the line is parallel to y = -1/2x + 1, the two lines have the same gradient.

therefore, m = -1/2

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3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

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4 years ago

What is the rule for finding the vertex of a formula in Standard form? Use that rule to

worty [1.4K]

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The x coordinate of the parabola is calculated using:

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The value of the x-coordinate is then plugged in, into the equation to calculate the y-coordinate, as follows:

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At the end of the calculation,

x and f(x) represent the horizontal and the vertical coordinates of the vertex.

Take for instance:

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The x-coordinate of the vertex is:

$x = -\frac b{2a}$

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$x = -\frac 44$

$x=-1$

The y-coordinate is:

$f(x) = 2x^2 + 4x - 9$

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$f(-1) =-11$

So, the vertex of $f(x) = 2x^2 + 4x - 9$ is (-1,11)

See attachment for illustration of vertex of $f(x) = 2x^2 + 4x - 9$

Read more about vertex of parabola at:

brainly.com/question/20209326

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2 years ago

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nordsb [41]

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3 years ago

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Oksanka [162]

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Step-by-step explanation:

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3 years ago