The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Hello there,
I hope you and your family are staying safe and healthy during this winter season.
We need to use the Quadratic Formula*
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Thus, given the problem:
So now we just need to plug them in the Quadratic Formula*
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As you can see, it is a mess right now. Therefore, we need to simplify it
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Now that's get us to the final solution:
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It is my pleasure to help students like you! If you have additional questions, please let me know.
Take care!
~Garebear
Answer:
400
Step-by-step explanation:
354>=350 and thus is rounded upwards to 400.
Answer:
I guess each friend gets 16 oranges and its gonna be uneven there is gonna be like 1 left over
Step-by-step explanation:
