the discriminant is:
D = (-1)^2 - 4*(-2)*6 = 49
We have a positive discriminant, which means that we have two real solutions.
<h3>
How to find the discriminant?</h3>
For the general quadratic equation, the discriminant is:
a*x^2 + b*x + c = 0
The discriminant is:
D = b^2 - 4ac
In this case, the quadratic equation is:
6*x^2 - x - 2 = 0
Then we have:
a = 6, b = -1, c = -2
Replacing that in the discriminant equation:
D = (-1)^2 - 4*(-2)*6 = 49
We have a positive discriminant, which means that we have two real solutions.
If you want to learn more about quadratic equations:
brainly.com/question/1214333
#SPJ1
Answer:
Its 5r, the 9r's cancel eachother out
Step-by-step explanation:
:) happy to help
1. To the question whether it is a good idea to design a drink can from a solid nonmetal, the answer is <u>No, because nonmetals lack luster</u>.
<h3>The Luster in Nonmetal</h3>
Non-metals do not have luster because they cannot reflect light from their surface with their dull appearances. Diamond and iodine are two exceptions to lustrous non-metals.
2. The reason it is not a good idea designing a drink can from a solid nonmetal is <u>No, because nonmetals are brittle.</u> Generally, solid nonmetals are known to be <u>dull and brittle</u>. They can easily break into pieces.
Thus, non-metals are <u>not ductile or malleable</u>.
Learn more about solid nonmetal here: brainly.com/question/825947
This is my very own step-step solution:
Step 1:
<span>Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : </span>
<span> 42*x^5*y^4-((-7*x^3*y)*(b))=0
</span>
Step 2:<span>Equation at the end of step 1 :</span><span>
((42•(x5))•(y4))-((0-(7x3•y))•b) = 0
</span>
Step 3:Pulling out like terms :
<span> 42x5y4 + 7x3yb</span> = <span> 7x3y • (6x2y3 + b)</span>
The correct is: 7x3y • (6x2y3 + b) = 0 <span>
</span>
Quick Side Note:
<span>Binomial can not be factored as the difference of two perfect cubes
</span>
I hope this helps a little!
Hope you have a great day!
5 lol it’s simple just use the two numbers in the middle or the one number in the middle
