One equivalent fraction for 4/21 could be 8/42.
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2
Answer:
-56
Step-by-step explanation:
Hello!
Let's create an equation to figure out what the middle integer really is.
Creating an equation:
n + (n + 1) + (n + 2) = -168 (This is true because we must account for the <em>consecutive integers </em>part.)
Simplifying:
3n + 3 = -168
Subtracting:
3n = -171
Dividing:
n = -57
Now, we plug-and-chug:
-57, -56, -54 (this is because we accounted for adding <em>positive </em>one.)
Thus, the middle integer is
.
Check:
We can see if we are correct by adding up -57, -56, -54.
(-57) + (-56) + (-54) = -168
So we are correct!
Hope this helps!
Answer:
36 degrees
Step-by-step explanation:
since, m<AOB is a right angle, we shall just create an equation:
M<AOB+M<BOC=90 degrees
Substitute: 6z-12+3z+30=90
Solve: 6z+3x=9z
-12+30=18
so, 9z+18=90 degrees
-18 -18
9z=72
z=8
So if z=8, then we should fit it so that it matches measure of AOB.
6z-12
6 times 8=48
48-12= 36
Answer: 
Step-by-step explanation:
Consider 
Substitute t= sinx
then dt = cos x dx

![[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]](https://tex.z-dn.net/?f=%5B%5Cint%20x%5Endx%3D%5Cdfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%2BC%5D)

Hence, 