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3 years ago

What is 0.6÷0.0024 ?

Mathematics

2 answers:

nata0808 [166]3 years ago

7 0

250 its corect dont worry

Vadim26 [7]3 years ago

6 0

250.

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What is a equivalent fraction for 4/21

joja [24]

One equivalent fraction for 4/21 could be 8/42.

3 0

2 years ago

In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.

bezimeni [28]

Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2

3 0

3 years ago

What is the middle integer?

Elanso [62]

Answer:

-56

Step-by-step explanation:

Hello!

Let's create an equation to figure out what the middle integer really is.

Creating an equation:

n + (n + 1) + (n + 2) = -168 (This is true because we must account for the consecutive integers part.)

Simplifying:

3n + 3 = -168

Subtracting:

3n = -171

Dividing:

n = -57

Now, we plug-and-chug:

-57, -56, -54 (this is because we accounted for adding positive one.)

Thus, the middle integer is $\boxed{-56}$ .

Check:

We can see if we are correct by adding up -57, -56, -54.

(-57) + (-56) + (-54) = -168

So we are correct!

Hope this helps!

7 0

2 years ago

Equation practice with angle addition

Triss [41]

Answer:

36 degrees

Step-by-step explanation:

since, m<AOB is a right angle, we shall just create an equation:

M<AOB+M<BOC=90 degrees

Substitute: 6z-12+3z+30=90

Solve: 6z+3x=9z

-12+30=18

so, 9z+18=90 degrees

-18 -18

9z=72

z=8

So if z=8, then we should fit it so that it matches measure of AOB.

6z-12

6 times 8=48

48-12= 36

6 0

2 years ago

Evaluate the integral. (Use C for the constant of integration.) cos(x) (8 + 7 sin^2(x)) dx

UNO [17]

Answer: $8 \sin x +7(\dfrac{\sin^3x}{3})+C$

Step-by-step explanation:

Consider $\int \cos(x) (8+7 \sin^2(x)) \, dx$

Substitute t= sinx

then dt = cos x dx

$\int \cos(x) (8+7 \sin^2(x)) \, dx = \int (8+7t^2)dt\\\\ =8t+7(\dfrac{t^3}{3})+C$

$[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]$

$=8 \sin x +7(\dfrac{\sin^3x}{3})+C$

Hence, $\int \cos(x) (8+7 \sin^2(x)) \, dx=8 \sin x +7(\dfrac{\sin^3x}{3})+C$

5 0

3 years ago