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3 years ago

What is 0.6÷0.0024 ?

Mathematics

2 answers:

nata0808 [166]3 years ago

7 0

250 its corect dont worry

Vadim26 [7]3 years ago

6 0

250.

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use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

I need three integers to make up 5 my integers are -1, -6, 9, 4, -7, -2, 8

satela [25.4K]

Answer:

You can get a negative 5 if you subtract -7 minus -2.

Step-by-step explanation:

4 0

3 years ago

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Ipatiy [6.2K]

Answer:

This is false

Step-by-step explanation:

7 0

2 years ago

The formula for the volume of a sphere is v= 4/3 3.14rWhat is the formula solved for r?

prohojiy [21]

Answer:

$r = \frac{3}{4\pi}V$

Step-by-step explanation:

First, the formula for the volume of a sphere is:

$V = \frac{4}{3}\pi r^3$

$\frac{3}{4}V = \pi r^3$

$\frac{3}{4}V\frac{1}{\pi} = r^3$

$r^3 = \frac{3}{4\pi}V$

$r = \sqrt[\leftroot{-2}\uproot{2}3]{\frac{3}{4\pi}V}$

If there is any steps you are unsure of, feel free to ask in the comments.

6 0

3 years ago

Please please help. Marking Brilliant for the correct answer

NISA [10]

Answer:

x = 19

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(x-7+4) * 4 = 8^2

(x-3)*4 = 64

Divide each side by 4

x-3 =16

Add 3 to each side

x-3+3 = 16+3

x = 19

5 0

3 years ago