Rewrite the function as:
y = -2/3x
Switch the variables x & y:
x = -2/3y
Solve for y:
x *-3/2 = -2/3y *-3/2
-3x/2 = y
So, the inverse is:
f^-1(x) = -3x/2
Domain — x > 1 (I notice opened dot.)
Range — y > 1
Answer:
Recursive form of sequence is given by f(n) = f(n-1) - 3
Step-by-step explanation:
The explicit form of sequence is given as
f(n) = −3n + 2
So nth term is given by
f(n) = −3n + 2
(n-1)th term is given by
f(n-1) = −3(n-1) + 2
We have
f(n) - f(n-1) = −3n + 2 - (−3(n-1) + 2)
f(n) - f(n-1) = −3n + 2 +3(n-1) - 2
f(n) - f(n-1) = −3n + 2 +3n -3 - 2
f(n) - f(n-1) = -3
f(n) = f(n-1) - 3
Recursive form of sequence is given by f(n) = f(n-1) - 3
Answer: hey im not sure, but i think your supposed to solve 7x-6 and 9+12x. Add these two together and times it by 55. Im not syre if this is right but u could try it.
Answer:
The line given is equal to y=-x+7 (Through rearranging)
To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):
-8=-5+c
c=-3
The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3