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3 years ago

Find the equation of the line through (0,-2) and (4, 18).

Mathematics

1 answer:

Montano1993 [528]3 years ago

3 0

Let me = slope

m = (18 - (-2))/(4 - 0)

m = 20/4

m = 5

We now plug slope 5 and one of the given points into the point-slope formula.

y - y_1 = m(x - x_1)

y - 18 = 5(x - 4)

y - 18 = 5x - 20

y = 5x - 20 + 18

y = 5x - 2

Done!

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Select the two values of x that are roots of this equation x^2-5x+2=0

Nataly [62]

The roots of the equation is x = 4.56 OR x = 0.44

<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

$x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}$

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

$x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}$

$x =\frac{5 \pm \sqrt{25-8} }{2}$

$x =\frac{5 \pm \sqrt{17} }{2}$

$x =\frac{5 + \sqrt{17} }{2}$ OR $x =\frac{5 - \sqrt{17} }{2}$

$x =\frac{5 + 4.12}{2}$ OR $x =\frac{5 - 4.12}{2}$

$x =\frac{9.12}{2}$ OR $x =\frac{0.88}{2}$

x = 4.56 OR x = 0.44

Hence, the roots of the equation is x = 4.56 OR x = 0.44

Learn more on Quadratic equation here: brainly.com/question/8649555

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3 0

2 years ago

What is an equation of the line that is perpendicular to −x+2y=4 and passes through the point (−2, 1) ?

Elza [17]

Answer:

y=-2x-3

Step-by-step explanation:

Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b. Therefore:

$-x+2y=4\\2y=x+4\\\\y=\frac{x+4}{2}\\\\y=\frac{1}{2}x+2$

Therefore, our slope is 1/2 and our y-intercept is 2. Now in order to determine a perpendicular line to the one stated above we must then get the negative inverse of our slope meaning $\frac{1}{2}=-2$ (negative reciprocal). Now we must use the point slope formula: