All categories

3 years ago

Find the equation of the line through (0,-2) and (4, 18).

Mathematics

1 answer:

Montano1993 [528]3 years ago

3 0

Let me = slope

m = (18 - (-2))/(4 - 0)

m = 20/4

m = 5

We now plug slope 5 and one of the given points into the point-slope formula.

y - y_1 = m(x - x_1)

y - 18 = 5(x - 4)

y - 18 = 5x - 20

y = 5x - 20 + 18

y = 5x - 2

Done!

You might be interested in

Help 10 minutes to turn in

olchik [2.2K]

When you express the equation of a line in the form $y=mx+q$ , the coefficient m is exactly the slope of the line.

So, let's manipulate the equation to fulfill our goal:

$12 = 4x-6y \iff 6y = 4x-12 \iff y = \dfrac{4}{6}x - 2 \iff y = \dfrac{2}{3}x-2$

So, the slope is 2/3

4 0

3 years ago

C) 15 X (-25) * (-4) X (-10 )<br><br>please say 100 points

natta225 [31]

Answer:

15 × (-25) × (-4) × (-10)

= 15 × 100 × 10

= 15000

4 0

3 years ago

The mean temperature for the first 4 days in January was 8°C. The mean temperature for the first 5 days in January was 7°C. What

mote1985 [20]

Answer:

The temperature of the 5th day was 3°C

Step-by-step explanation:

Mean temperature of the first 4 days = 8°C

Note that:

Mean = Sum of temperatures ÷ number of days

∴ 8 = sum of temperature ÷ 4

$= 8 = \frac{sum\ of\ temperatures}{4}$

$= sum\ of\ temperatures\ = 8\ \times\ 4 = 32$

Therefore the sum of the first 4 days = 32

Let the temperature of the next day (the fifth day) be m

Hence,

sum of the temperatures of first 5 days = 32 + m - - - - (1)

Next, the sum of the first 5 days can be calculated from the given average of the first 5 days as follows:

Mean temperature of the first 5 days = 7

$Mean = \frac{sum\ of\ temperatures}{number \ of\ days}\\\\7 = \frac{sum\ of\ temperatures}{5} \\sum\ of\ temperatures\ = \ 7\ \times\ 5\ = 35\\sum\ of\ temperature\ of\ the\ first\ 5\ days\ =\ 35 - - - - - (2)$

Now, you will notice that equation (1) = equation (2)

∴ 32 + m = 35

m = 35 - 32 = 3

therefore, the temperature of the 5th day was 3°C

4 0

3 years ago

Please answer quick I will give brainliest to the first answer Mr. Morris is going to save money and replace his sailboat's main

Sindrei [870]

the base is 20 ft so the triangular base is 69 feet.

4 0

3 years ago

una escalera de 12ft de longitud esta apoyada contra una pared, de modo que su base se encuentra a 4 ft de la pared a nivel del

Marrrta [24]

Answer:

Step-by-step explanation:

Altura = 11.312 pies

i) La escalera que descansa contra la pared formará un triángulo en ángulo recto.

ii) la escalera formará la hipotenusa del triángulo rectángulo dado por h = 12 pies.

iii) La base está dada por 4 pies.

iv) de la fórmula del triángulo en ángulo recto.

base = $altura = \sqrt{hipotenusa^{2}\hspace{0.15cm}- \hspace{0.15cm} base^{2} } = \sqrt{12^{2}\hspace{0.15cm} - \hspace{0.15cm}4^{2} } = \sqrt{144\hspace{0.15cm} - \hspace{0.15cm}16} = \sqrt{128} = \hspace{0.15cm}8\sqrt{2} = 8\times1.414 = 11.312 pies$

6 0

3 years ago