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3 years ago

13

According to the Ruler Postulate, what does the set of points on any line correspond to?

2 answers:

Elan Coil [88]3 years ago

8 0

Answer:

<u><em>The answer is</em></u>: <u>With real numbers.</u>

Step-by-step explanation:

<em><u>The rule postulate states that</u></em>: Each point of a line can be matched with a real number.

<u><em>The answer is</em></u>: <u>With real numbers.</u>

Studentka2010 [4]3 years ago

5 0

You answer will be real numbers

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3 years ago

Evaluate the expression for <br> x = 4, y=-2, z= -3.<br> 2² + 8zy - y²

andrew11 [14]

Answer:

Pretty sure its 53

Step-by-step explanation:

9+48-4

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3 years ago

Read 2 more answers

Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s

Margaret [11]

Answer:

$QR = 6.0033$

$QS = 8.22$

$RS = 6.0033$

QRS is isosceles

Step-by-step explanation:

Given

See attachment for complete question

From the attachment, we have the following parameters $QR = \sqrt{(-3-0)^2+(-5.2-0)^2}$

$QR = \sqrt{9+27.04}$

$QS = \sqrt{(-3-5)^2+(-5.2-(-3.322))^2}$

$QS = \sqrt{64+3.53} = \sqrt{67.53$

$RS = \sqrt{(0-5)^2 + (0 - (-3.322))^2}$

$RS = \sqrt{(25 + 11.04}$

Solving further, we have:

$QR = \sqrt{9+27.04}$

$QR = \sqrt{36.04}$

$QR = 6.0033$

$QS = \sqrt{64+3.53} = \sqrt{67.53}$

$QS = 8.22$

$RS = \sqrt{25 + 11.04}$

$RS = \sqrt{36.04}$

$RS = 6.0033$

From the calculations;

$RS = QR = 6.0033$

<em>This means that: QRS is isosceles</em>

8 0

3 years ago

(x/2)+3=(3/4) I don't understand can someone help?

arlik [135]

Answer:

What are you trying to find?

Step-by-step explanation:

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3 years ago

Read 2 more answers

Partial fraction decomposition<br> 20x+9/25x^2+20x+4

ozzi

Step-by-step explanation:

We have

$\frac{20x + 9}{25 {x}^{2} + 20x + 4 }$

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

$\frac{20x + 9}{(5x + 2) {}^{2} }$

Now, we must think of two fractions that

$\frac{a}{(5x + 2) {}^{2} } + \frac{b}{5x + 2}$

We use a perfect square term for one fraction, then a linear one for the next, because if we set both of the denomiator to the same factor, we would get a inconsistent system.

So right now, we have

$\frac{a}{(5x + 2) { }^{2} } + \frac{b}{5x + 2} = \frac{20x +9 }{25 {x}^{2} + 20x + 4 }$

$a + (5x + 2)b = 20x + 9$

$5b (x)= 20$

$a + 2b = 9$

$b = 4$

so that means that a is

$a + (2)(4) = 9$

$a + 8 = 9$

$a = 1$

So our equation is

$\frac{1}{(5x + 2) {}^{2} } + \frac{4}{5x + 2}$

6 0

2 years ago