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skelet666 [1.2K]
3 years ago
15

Jordan likes only blue jelly beans. He has a box of 100 jelly beans that contains equal numbers of red, blue, green, yellow, and

orange jelly beans.
Jordan randomly pulls out a jelly bean. Then he pulls out a second one without replacing the first. What is the probability that both jelly
beans are blue?
Mathematics
1 answer:
spin [16.1K]3 years ago
3 0
2/20 is the chance of choosing 2 blue jelly beans. Since there are 5 colors, that are equally divided......
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I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
lawyer [7]
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is  = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated. 
5 0
3 years ago
How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

8 0
3 years ago
You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of
worty [1.4K]
Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.
7 0
3 years ago
Justin writes the letters illinois on cards and then places the cards in a hat. What are the odds in favor of picking an I.
kirill115 [55]
Probablity=desiredoutcomes/totalpossible
total possible=number of cards or number of letters which is 8 letters

desired is number is the letter "I", which is 3
3/8 is probality
in favor it is 3:5, because we are looking at odds of picking vs not picking
not is 5/8
3:5 s answer
A is answer
5 0
3 years ago
What is the value of 35 To the second power
creativ13 [48]
1225.
It is also called 35 squared. It is 35X35
The power is how many times you multiply the number by itself. 
6 0
3 years ago
Read 2 more answers
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