Answer:
41
Step-by-step explanation:
40+16+y=180°
56+y=180°
y=180-56
y=124°
124+15+x=180°
139+x=180°
x=180-139
<em>x=41°</em>
Answer:
The first 5 terms are 2, 5, 8, 11, 14.
Step-by-step explanation:
- You use the formula to find out each term.
- f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
- Now to find each term:
- n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
- n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
- n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
- n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
- n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14
So the first 5 terms are 2,5,8,11,14
1/3×7= 7/3
2 2/3×9= 8/3 x 9 = 72/3 = 24
3 1/5÷8= (16/5 ) / 8 = 16/5 x 1/8 = 16/40 = 4/10 = 0.4
For this case we have that by definition, the equation of the line in a slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have the following equation:

Thus, the slope is 
By definition, if two lines are perpendicular then the product of the slopes is -1.

We find

Thus, the equation of the line is:

We substitute the given point to find "b":

Thus, the equation of a line perpendicular to the given line and passing through the given point is:

Answer:

5(b-3c)
Divide the entire polynomial by 5, as that is the only factor that is common throughout the entire polynomial.