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Anni [7]
3 years ago
7

What is 75.96 rounded to the nearest once place

Mathematics
2 answers:
In-s [12.5K]3 years ago
3 0
76.0 would be your answer 
dem82 [27]3 years ago
3 0
76.0 is the correct rounding of the Tenths place 
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The rate is 10.02 and I found that by dividing x with y
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3 years ago
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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).
spayn [35]

The Bernoulli distribution is a distribution whose random variable can  only take 0 or 1

  • The value of E(x2) is p
  • The value of V(x) is p(1 - p)
  • The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * (1- p) + 1^2 * p

Evaluate the exponents

E(x^2) = 0 * (1- p) + 1 * p

Multiply

E(x^2) = 0 +p

Add

E(x^2) = p

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Start by calculating E(x) using:

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * (1- p) + 1 * p

E(x) = p

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = p - p^2

Factor out p

V(x) = p(1 - p)

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

E(x^{79}) = \sum x^{79} * P(x)

So, we have:

E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p

Evaluate the exponents

E(x^{79}) = 0 * (1- p) + 1 * p

Multiply

E(x^{79}) = 0 + p

Add

E(x^{79}) = p

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0
2 years ago
6 ) y = -x + 4<br> slope =<br> y-intercept =<br> What it is the answers to the question above
maksim [4K]
Slope= -1
Y-intercept= 4
7 0
3 years ago
Suppose x and y vary inversely, and x =10 when y=8. Write the function the models the inverse variation.
Damm [24]

Answer:

sorry ya please forgive me

5 0
3 years ago
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
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